x^(2/3)-4x^(1/3)-5=0

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Solution for x^(2/3)-4x^(1/3)-5=0 equation: 


x in (-oo:+oo)

x^(2/3)-(4*x^(1/3))-5 = 0

x^(2/3)-4*x^(1/3)-5 = 0

t_1 = x^(1/3)

1*t_1^2-4*t_1^1-5 = 0

t_1^2-4*t_1-5 = 0

DELTA = (-4)^2-(-5*1*4)

DELTA = 36

DELTA > 0

t_1 = (36^(1/2)+4)/(1*2) or t_1 = (4-36^(1/2))/(1*2)

t_1 = 5 or t_1 = -1

t_1 = -1

x^(1/3)+1 = 0

1*x^(1/3) = -1 // : 1

x^(1/3) = -1

( -1 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 5

x^(1/3)-5 = 0

1*x^(1/3) = 5 // : 1

x^(1/3) = 5

x^(1/3) = 5 // ^ 3

x = 125

x = 125

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